CHO RDA, COMPC, COMPA, and all that sort of stuff
Posted: Sat Feb 21, 2015 11:45 pm
I'm wondering about the example from the Knowedge Base, whether possibly the highlighted line below should have a COMPC instead of COMPA? Please confirm.
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If COMPA is not used, as in the code above, then the COMPC will need to be used in the first line only, but if COMPA is used, then COMPC should be in the second line:
cho rda,sin0,sin|reg|compa,cdel+100
cho rda,sin0,sin|compc,cdel+101
Notice that the first line specifies a midpoint in the CDEL memory space, and the second line indicates a position that is 1 memory location greater.
For a wild set of chorus outputs, you can set up a single sine LFO and get 4 outputs, that we'll call c1 through c4:
cho rda,sin0,sin|reg|compc,cdel+800
cho rda,sin0,sin,cdel+801
wrax c1,0
cho rda,sin0,sin|reg|compa,cdel+400
cho rda,sin0,sin|compa,cdel+401
wrax c2,0
cho rda,sin0,cos|reg|compc,cdel+1100
cho rda,sin0,cos,cdel+1101
wrax c3,0
cho rda,sin0,cos|reg|compa,cdel+1400
cho rda,sin0,cos|compc,cdel+1401
wrax c4,0
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Thanks,
DL
=============================================
If COMPA is not used, as in the code above, then the COMPC will need to be used in the first line only, but if COMPA is used, then COMPC should be in the second line:
cho rda,sin0,sin|reg|compa,cdel+100
cho rda,sin0,sin|compc,cdel+101
Notice that the first line specifies a midpoint in the CDEL memory space, and the second line indicates a position that is 1 memory location greater.
For a wild set of chorus outputs, you can set up a single sine LFO and get 4 outputs, that we'll call c1 through c4:
cho rda,sin0,sin|reg|compc,cdel+800
cho rda,sin0,sin,cdel+801
wrax c1,0
cho rda,sin0,sin|reg|compa,cdel+400
cho rda,sin0,sin|compa,cdel+401
wrax c2,0
cho rda,sin0,cos|reg|compc,cdel+1100
cho rda,sin0,cos,cdel+1101
wrax c3,0
cho rda,sin0,cos|reg|compa,cdel+1400
cho rda,sin0,cos|compc,cdel+1401
wrax c4,0
=============================================
Thanks,
DL